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ProblemSet2 - {$3 6[[email protected]?an mwmnou 20 WONG/nee...

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Unformatted text preview: {$3} 6! [WWI @1119?an mwmnou 20% WONG/nee DlSAPPEhRs N 34 whens Fat CA0? O‘OW M/L Cm: 0&8 /L §§§§§§ F? WW W WON WWW We usxmeaarmca wwwwww gggfig OF THE, WWW $3355 . S w}? . ' aggagg Si T’QMROML DiSWRMCE ' gg ggfi rs mmwcem op ““1? 9&1“ ORDER same i {N mm. CONCENTEA'mN _ i "din = L C; W99. (w; 1' °‘* - - A3 r at CM 70%, W3 A/Vi‘5’o°/o £6:an 1,3520; kt C: @8060 @ 'E: 34w~016$ C“ - /\ . 7”, C [ fab . , \fi ULEOCQ 3' k (34mm\ 0:- 25-, d,” ‘\ " “*9 .‘ ‘ E . [6 \HQ’QB , W fx‘ 34 mm : Ln ( LZSN 3‘4 MN :- 012513 EMMA] XL : (9.565% QO-gmwfll “.- PAUL fl '5? R C“: or T: C901 (D Em H; tieerfiOR m t 80% m: 35% XAE: (Pal—70%? -—/' ' .‘,.- \. ‘_, —» ,' »—\ ' "4» K I, _ dCP‘ I“ L C \L/ f ( .. k. Mb Ht. Wt gamma; we mug fitfiCTioH. "T“ ' “ A» ‘2“ (5% 7 fit: N fl n E 8; 1570206}: RENE ‘ééiELE fli/Wm‘) (WSW? NM PM g (‘QrJSf'f'wf-Jl‘; 5%“ x I W W M / \ .— ‘ A : r“ H H XAC WYAC ‘ (EON ST) ‘ CFO H 0 M— ~ ’ "” Ir/ Chg as Q I SP m T _ if \J/ :1. ‘1 f 2* F: m c, an ' ' ‘ Kc :7— é KL: EFL ‘5 t—li (FED/A 95:0 K: 52 \‘er goJmTEl Kc ./6 L - M 4 7‘ k1 I \ ~ y’zé‘f ’U c 8 m 5 § § QEQ ‘7 a / kUNI)JJ —\[\£kr _i.\,.’L‘>__. J,“ kifléa \‘J‘VA/V‘” Wm KM 1a \\ Kn , K ~ln (kw WWW“ up L/t I k V“? / “L“ (K, A» : {Lfix+\<1\z+~ (m -— \(\(OICS\ T (14‘ JrkZSS‘KOA/‘MJ OJoCi-S ‘ \4( JV k2 Sflwd _‘ /: 1<fk kz:_‘0‘08‘(0_(QLk Mm (W) CK ha (a E491“:LBP;£E; 0.9%} 0}: A \3 (of’i'di(~’TED [ELJJWWWN CEM‘SVIWT / 0,3723 0? A PQV‘RMS W V * V "A‘ I \ Av '7? VOL @ @wurgmm szg-(O(‘3'L‘-;>f\j\_o¢gxfi) < 3‘55); “T K: Gee : \q i L. JL —; K v r 'A Cm- = (05% (0333) 7 0‘ My; L \ 2'2: 1" rift}: k\ __ Cw. 9,5) L- 7 Z 14‘ 0, was "3— :g E by 2:: I l "a x? E 2‘ Hr 34: / DJLD ~\/\../\~/ \_( C1: F\()LJ£:;CLJ<) f\ 6) L450“ \ L, / » a - 1‘ “w v\: a P 3mm vuwt 1.11 < h 1‘ t ( ’/1«‘\ l M ‘3 1 Or) EGO ”goo ”:1 ‘3’ 300 2'39 “'10P. Q0: SOON/r1” '36“) 1"ka é‘fi‘cy‘x R€?\CV<:5€. _§m6’QOWW {fie-K [\AUL Wow (.1 at: Q, : (100 / 111‘ ’5‘ 00 m a N E L C) LAO: L300 JC : (00 €753 {: 1 ZOO 1 :33) E 1 30¢) ‘\ 5CD l lmmwcéfm mm A 6mm EEJ‘VSWR XAZ? g) f 100mm) :7 (if PMD‘HE‘flWQEfiQON armAamm AFW? S"WwRS c: :20011/ @ 1:10 Problem 3.11 Time (min) CA (mol/m3) In (Ca) 1 [Ca 0 1000 6.907755 0.001 100 500 6.214608 0.002 200 333 5.808142 0.003003 300 250 5.521461 0.004 400 200 5.298317 0.005 Plot of Ca vs. Time (0 Order) y = -1.85x + 826.6 R2 = 0.813 O 1 1 w 0 100 200 300 400 Time(min) In Ca vs. Time (15! Order) y = —0.0039x + 6.7325 R2 = 0.9472 In (Ca) 0 100 200 300 400 Time (min) 1 /Ca vs. Time 0.005 — 0.0045 y =1E—05x + 0.001 0.004 7 R2 = 1 0.0035 0.003 0.0025 7 0.002 7 0.0015 0.001 1/Ca 0 100 200 300 400 Time (min) <3 1 '4 2 . ”‘1??— VM LLCW , ‘0“ 0mm Facet; 7 F: WWW 0F WWLE ms 9. \w E :3? E 5 kg”? \mi/IOSQg/j : - LJC @ fi: 79/»!er m D U (D H (D T‘v’v‘i ~i<rb\omixw [113th To 9 ,_,4 #A sou/ass . SQUARE sumac; sou-mil nnnnnn 2m SHEETS EYEfifisé' 3C0 FEC‘V’CLEG WHITE 5m W513. FILLER 43m 50 SHEETS EVE-EASE' ~38? 1m SHEE TS EVE-EASE” 3 7152 2 Z 2’ 339 2% 2438 ququququ SQUARE SQUARE ' MRECYCLEC WHITE cu SJ W L G 3mm (26mm! Rama =7 Humw} awe PUJN66D (M0 mum MFER (£0013 We £245;wa Q law 2%: (No {*th W'fimw) Ramon: 2A a... B Ems (HT oveaweaamb c? NOR 257%st F: Em A we memom w wows 0:; m, mealtmwwes HWY FLT Dam . R“ : mum. mama, 6&3er ‘ 5L TV: mmmmfle @t SI RI: p30” M (W‘Wb TR): \N\T1P(LPWQE pv:nR'Y P90: \KTM @ 233C R: 51:71; PM: [am ”536% P} = 31 M34928“ ”E T2 _ 313.15% # , pm - PM” 7.01.3.6!“th _ P", if; Zr E; l c qu= (2955 mm “av—— -flw— . @490 Tzloo‘”; “:2 cm=2+l=4 PA. : \ll‘MSS PM ~ «5%- (v ‘ mm '1 LZSlssh-rm + 211» '~— Hams} PA "~ 2W —h23155 I a“ 1 ”mm weawa ea in SE? W651” FOP om mmmumon a: ms at ? .0... -J VG 'RT (EMS) SEE \CTOchePaoT : M? LsNEfifi BCCSEKT H6905}: Q = E: m" k if. {ARC/M: nfl “H '1 I? § iav fa 1“ ~\ 19,0 _ ;' Wt .15 : [$3.er + L SE? Zdoebée Pm : mee A L quart mm mum: weagssww ' SLOPE : if: : 0:20{O%~—~—-l 50.7 SHEETS. PM. ER 5 SQUARE 42-333 {>0 SHEEXS tj‘rE-EJGE‘ 5 SQUARE 1W ENE-B's LTE-EIEE' ‘5 SQUARE 1m HECYCLfiD WHITE 550W}? 5; ' 5&9 MSHEEYS D'E‘EAE' SSOUARE «2 392 393 alonficv‘cmb wmIE bsotWIE 38? 3178? um: m u 12 ‘2 42 WW Problem 3.21 Time Pressure Pa 1n(Pa) 1/Pal minutes atm atm mm1 0 1.25155 1.25155 0.224383 0.799009 1 1.14 1.02845 0.028053 0.972337 2 1.04 0.82845 -O.1882 1.207073 3 0.982 0.71245 —0.33905 1.403607 4 0.94 0.62845 —0.4645 1.591216 5 0.905 0.55845 -0.58259 1.790671 6 0.87 0.48845 —0.71652 2.047292 7 0.85 0.44845 —0.80196 2.229903 8 0.832 0.41245 -0.88564 2.424536 9 0.815 037845 4197167 2.642357 10 0.8 0.34845 4.05426 2.869852 15 0.754 0.25845 4.36082 3.899396 20 0.728 0.20445 4.58743 4.891171 First Order Plot 0.5 O E 76“ -O.5 2-. E -1 J -1.5 -2 ......... .2 - H » W......._1 Second Order Plot . 3”” = 0.2063x + 0.734 . 1? R2 = 0.9998 .5 .‘3 N o. “‘— 3 g E O 5 1O 15 20 25 time (minutes) 3.25 t(min) Pa (mm hg) (Pa-Pae)I(Pa0-Pae)-|n((Pa-Pae)l(Pa0-Pae)) 0 760 1 0 2 600 0737704918 0304211374 4 475 0.532786885 -0.629633775 6 390 0393442623 0932820034 8 320 0278688525 -1.27766052 10 275 0.204918033 —1.58514522 12 240 0.147540984 —1.913649287 14 215 0.106557377 —2.239071687 inf 150 |' Chart Title y = -O.1603x + 0.0119 R2 = 0.9999 |n(Pa-PaE)/(Pa0-PaE) Time (min) 15—0 \ (pm—lwma) “ .m 6.5)1‘4 _; 3.7.1] GIVEMZ 1A —-' R P: £br16+anf \nA‘xaazé'Sm/o A +13 M Fmafl TA (Lamas 5% 7.0% it“: 1370va ML: WSLM ...
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