problem01_70 - . 2 = 62 north of east, which is = - 28 62...

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1.70: The third leg must have taken the sailor east a distance ( 29 ( 29 ( 29 km 33 . 1 km 00 . 2 45 cos km 50 . 3 km 80 . 5 = - - and a distance north ( 29 ( 29 km 47 . 2 45 sin km 5 . 3 = The magnitude of the displacement is km 81 . 2 ) km 47 . 2 ( ) km 33 . 1 ( 2 2 = + and the direction is arctan ( 29 33 . 1 47
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Unformatted text preview: . 2 = 62 north of east, which is = - 28 62 90 east of north. A more precise answer will require retaining extra significant figures in the intermediate calculations....
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