problem01_70 - 2 = ° 62 north of east which is ° = °-°...

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1.70: The third leg must have taken the sailor east a distance km 33 . 1 km 00 . 2 45 cos km 50 . 3 km 80 . 5 and a distance north km 47 . 2 45 sin km 5 . 3 The magnitude of the displacement is km 81 . 2 ) km 47 . 2 ( ) km 33 . 1 ( 2 2 and the direction is arctan
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Unformatted text preview: . 2 = ° 62 north of east, which is ° = °-° 28 62 90 east of north. A more precise answer will require retaining extra significant figures in the intermediate calculations....
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