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1.68:
a)
x
x
x
x
C
B
A
R
+
+
=
(
29
(
29
(
29
(
29
(
29
(
29
(
29
(
29
(
29
(
29
(
29
(
29
m.
3
.
5
60
180
sin
m
0
.
6
40
sin
m
00
.
15
37
90
sin
m
0
.
12
and
m,
7
.
15
60
180
cos
m
0
.
6
40
cos
m
00
.
15
37
90
cos
m
0
.
12

=
+
+

+

=
+
+
=
=
+
+

+

=
y
y
y
y
C
B
A
R
The magnitude of the resultant is
m
6
.
16
2
2
=
+
=
y
x
R
R
R
, and the direction from
the positive
x
axis is arctan
(
29
6
.
18
7
.
15
3
.
5

=

. Keeping extra significant figures in the
intermediate calculations gives an angle of
,
49
.
18
°

which when considered as a
positive counterclockwise angle from the positive
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Unformatted text preview: xaxis and rounded to the nearest degree is 342 . b) ( 29 m; 14 . 5 m 58 . 9 m 64 . 9 m 20 . 5 m; 71 . 21 m 49 . 11 m 22 . 7 m 00 . 3==== y x S S 3 . 13 ) 71 . 21 ( ) 14 . 5 ( arctan = = θ m 3 . 22 ) m 14 . 5 ( ) m 71 . 21 ( 2 2 =+= S...
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This homework help was uploaded on 02/14/2008 for the course PHYS 112 taught by Professor Wheeler during the Spring '08 term at Cornell University (Engineering School).
 Spring '08
 Wheeler

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