problem01_39 - 29 . 202 4 . 26 8 . 10 =--Note that 180 must...

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1.39: Using components as a check for any graphical method, the components of B are m 4 . 14 = x B and m, 8 . 10 = y B A has one component, m 12 - = x A . a) The - x and - y components of the sum are 2.4 m and 10.8 m, for a magnitude of ( 29 ( 29 m, 1 . 11 m 8 . 10 m 2.4 2 2 = + , and an angle of . 6 . 77 2.4 10.8 = b) The magnitude and direction of A + B are the same as B + A . c) The x - and y- components of the vector difference are – 26.4 m and m, 8 . 10 - for a magnitude of m 28.5 and a direction arctan (
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Unformatted text preview: 29 . 202 4 . 26 8 . 10 =--Note that 180 must be added to ( 29 ( 29 22 arctan arctan 4 . 26 8 . 10 4 . 26 8 . 10 = =--in order to give an angle in the third quadrant. d) . m 8 . 10 m 4 . 26 m . 12 m 8 . 10 m 4 . 14 j i i j i A B + = + + =- ( 29 ( 29 . 2 . 22 26.4 10.8 arctan of angle and at m 5 . 28 m 8 . 10 m 26.4 Magnitude 2 2 = = + =...
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This homework help was uploaded on 02/14/2008 for the course PHYS 112 taught by Professor Wheeler during the Spring '08 term at Cornell University (Engineering School).

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