M408K Review 3 - Mahon, Kevin Review 3 Due: Dec 9 2005,...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Mahon, Kevin – Review 3 – Due: Dec 9 2005, 6:00 pm – Inst: Edward Odell 1 This print-out should have 18 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. The due time is Central time. 001 (part 1 oF 1) 10 points IF f - 1 is the inverse oF f , determine the value oF f ( f - 1 (6)). 1. f ( f - 1 (6)) = 1 6 2. f ( f - 1 (6)) = 1 36 3. f ( f - 1 (6)) = 6 4. f ( f - 1 (6)) = 36 5. Need to know f 002 (part 1 oF 1) 10 points ±ind the inverse Function, f - 1 , oF f when f is defned by f ( x ) = 4 x - 7 , x 7 4 . 1. f - 1 ( x ) = 1 4 p x 2 - 7 , x 0 2. f - 1 ( x ) = 1 4 ( x 2 + 7) , x 0 3. f - 1 ( x ) = 1 7 p x 2 - 4 , x 0 4. f - 1 ( x ) = 1 4 ( x 2 + 7) , x 4 7 5. f - 1 ( x ) = 1 7 ( x 2 - 4) , x 7 4 6. f - 1 ( x ) = 1 7 p x 2 + 4 , x 4 7 003 (part 1 oF 1) 10 points ±ind the value oF g 0 ( - 1) when g is the inverse oF the Function f defned by f ( x ) = 2 x 3 - 1 x . ( Hint : f ( - 1) = - 1.) 1. g 0 ( - 1) = - 7 2. g 0 ( - 1) = - 2 3. g 0 ( - 1) = - 1 7 4. g 0 ( - 1) = 7 5. g 0 ( - 1) = 2 6. g 0 ( - 1) = 1 7 004 (part 1 oF 1) 10 points ±ind f ( x ) when f 0 ( x ) = 7 cos x - 8 sin x and f (0) = 2. 1.
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 04/15/2008 for the course M 408k taught by Professor Schultz during the Fall '08 term at University of Texas at Austin.

Page1 / 5

M408K Review 3 - Mahon, Kevin Review 3 Due: Dec 9 2005,...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online