problem01_59 - 10 156 . 3 Hz 10 1.42 26 9 7 9 = d) ( 29 (...

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1.59: a) To three significant figures, the time for one cycle is s. 10 04 . 7 Hz 10 420 . 1 1 10 9 - × = × b) h cycles 10 11 . 5 h 1 s 3600 s cycles 10 1.420 12 9 × = × × c) Using the conversion from years to seconds given in Appendix F, ( 29 ( 29 . 10 06 . 2 y 10 600 . 4 y 1 s
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Unformatted text preview: 10 156 . 3 Hz 10 1.42 26 9 7 9 = d) ( 29 ( 29 s. 10 4.60 by off be d clock woul the so , y 10 00 . 1 10 4.60 y 10 4.600 4 5 4 9 =...
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This homework help was uploaded on 02/14/2008 for the course PHYS 112 taught by Professor Wheeler during the Spring '08 term at Cornell University (Engineering School).

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