problem01_54 - 2 m 130 37 sin m . 18 m 12-=-= = y x z B A C...

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1.54: a) From Eq. (1.22), the magnitude of the cross product is ( 29 ( 29 ( 29 2 m 130 37 180 sin m 0 . 18 m 0 . 12 = - The right-hand rule gives the direction as being into the page, or the – z -direction. Using Eq. (1.27), the only non-vanishing component of the cross product is ( 29 ( 29 ( 29
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Unformatted text preview: 2 m 130 37 sin m . 18 m 12-=-= = y x z B A C b) The same method used in part (a) can be used, but the relation given in Eq. (1.23) gives the result directly: same magnitude (130 m 2 ), but the opposite direction (+ z-direction)....
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This homework help was uploaded on 02/14/2008 for the course PHYS 112 taught by Professor Wheeler during the Spring '08 term at Cornell University (Engineering School).

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