problem01_42 - d 2 2 cm 6 cm 80 2 = 6.62 cm arctan 29 80 2...

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1.42: a) The x - and y -components of the sum are 1.30 cm + 4.10 cm = 5.40 cm, 2.25 cm + (–3.75 cm) = –1.50 cm. b) Using Equations (1-8) and (1-9), 2 2 ) cm 50 . 1 ( ) cm 0 4 . 5 ( = 5.60 cm, arctan 40 . 5 50 . 1 = 344.5 o ccw. c) Similarly, 4.10 cm – (1.30 cm) = 2.80 cm, –3.75 cm – (2.25 cm) = –6.00 cm.
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Unformatted text preview: d) 2 2 ) cm . 6 ( ) cm 80 . 2 (-+ = 6.62 cm, arctan ( 29 80 . 2 00 . 6-= 295 o (which is 360 o – 65 o )....
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