Q1soln - MAE140 Linear Circuits Quiz # 1 - January 29, 2002...

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MAE140 Linear Circuits Quiz # 1 --- January 29, 2002 Answers Question 1 (a) 1. Power is proportional to v 2 /R or R v 2 /P . Thus, if a 100W bulb has resistance of 60 , then a 50W bulb should have a resistance of 120 . 2. If we double the voltage from 110V to 220V, then for the same power we need to take four times the resistance. So a 100W bulb for Europe would have a resistance of 240 . (b) Label the currents and voltages as shown. In this formulation, the power of each element is given by the product of its applied voltage and its induced current into the positive voltage terminal. 1. The current in the resistor is always i R =v S /R because the voltage across it is always v R =v S . Thus the power absorbed by the resistor is i R v R =v S 2 R regardless of the current source action. 2. The voltage across the current source v ICS = v S . The current is i ICS =-i S . Thus the power delivered by the current source is always - i S v S . The direction of current and voltage shown imply that this is always negative, so that the current source always supplies power. 3.
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This note was uploaded on 01/17/2009 for the course MAE MAE 140 taught by Professor Mauricio during the Fall '04 term at UCSD.

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Q1soln - MAE140 Linear Circuits Quiz # 1 - January 29, 2002...

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