Q2soln

# Q2soln - MAE140 Linear Circuits Quiz 2 Answers Question...

This preview shows pages 1–2. Sign up to view the full content.

# 2 --- February 21, 2002 Answers Question 1 (Thomas & Rosa 4-7) Nodal analysis yields: Node C: v D =v S Node D: grounded v D =0 Node A: v A =v X 0 10 10 2 1 10 10 1 10 10 1 10 4 1 10 2 1 3 3 3 3 3 = + × × × + × + × A S B A v v v v Node B: 0 10 10 20 1 10 10 1 10 10 1 3 3 3 = × + × + × A B A v v v This may be jointly written as S B A S B A v v v v v v = × = × × × × 0 10 3 001 , 200 2 017 , 200 0 10 20 10 10 20 3 10 20 002 , 200 10 20 2 10 20 017 , 200 3 3 3 3 3 Now note that v B =v O . So S S S B O v v v v v 10 9978 . 9 3 002 , 200 2 017 , 200 0 002 , 200 10 017 , 200 = = = Question 2 (Thomas & Rosa 4-34) (a) Node B: () . 0 , 0 1 2 1 2 = + + = C B A n v G v G G

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 3

Q2soln - MAE140 Linear Circuits Quiz 2 Answers Question...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online