ssm_ch32 - Chapter 32 3 H H ~ ~ ~ ~(a Use Gauss law for...

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where A is the area of a plate and E is the magnitude of the electric field between the plates. The field between the plates is uniform, so E = V=d ,whe re V is the potential difference across the plates and d is the plate separation. Thus i d = ² 0 A d dV dt : Now ² 0 A=d is the capacitance C of a parallel-plate capacitor without a dielectric, so i d = C dV dt : 21 (a) For a parallel-plate capacitor, the charge q on the positive plate is given by q =( ² 0 A=d ) V , where A is the plate area, d is the plate separation, and V is the potential difference between the plates. In terms of the electric field E between the plates, V = Ed ,so q = ² 0 AE = ² 0 © E ,whe re ©
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ssm_ch32 - Chapter 32 3 H H ~ ~ ~ ~(a Use Gauss law for...

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