GES_100_HW_2_solutions

# GES_100_HW_2_solutions - GES-100 HW-2(Chaps 1,2,4 SOLUTIONS...

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Unformatted text preview: GES-100 HW-2 (Chaps. 1,2,4) SOLUTIONS Chap 1, Exercise 11 : The system is in equilibrium , meaning that the net force must be zero. Since the net upwards force is 200N+200N = 400N, we know that the net downward force must also be 400N. Since the person’s weight is given as 250N, then the staging must weigh: 400N – 250N = 150N. Chap. 1 Exercise 12 : We again note that the system is in equilibrium , meaning that the net force must be zero. The net downwards force is 250N + 300N + 300N = 850N. Thus the net upward force must also equal 850N. Since the tension on the left rope is given as 400N, the tension on the right rope must be 850N-400N = 450N. Thus the right scale would read 450N. Chap. 1 Exercise 20: The problem tells us that the speed is increasing, therefore the crate is accelerating , meaning there must be a net force greater than zero. Thus the force of your push must be greater than the force of friction....
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## This note was uploaded on 04/15/2008 for the course GES 100 taught by Professor Pinter during the Fall '07 term at CSU San Marcos.

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GES_100_HW_2_solutions - GES-100 HW-2(Chaps 1,2,4 SOLUTIONS...

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