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Fall 2008 Exam 2 Soln

# Fall 2008 Exam 2 Soln - ltz’ﬂrw Pa.”:03 TLSF’L...

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Unformatted text preview: ltz’ﬂrw Pa.” :03 TLSF’L * gﬁfuh‘o,‘ A 5’ 6 NW Peggimﬁ Bw%: "#2: M 5 6 “L! m "its-2.62“ Mam I ‘ L 15 .3 -~ ﬁbgf-Q‘nl .Mflg{._2r,3 I ’ O (0' g I —' 0 ~10 it PM» ﬂank maven/IL 56 c, k Umrv':r ~—{ 4 -3 TL “8 .6 J ‘* IM ., {ﬁg 20 MW 5% yaw: (owe) (4—0 mo; «90‘ «90K \Mu —:- ~LLW w: CDC—+0 wk (3) VE%€ Problem 2 (25 Points) The crate of unknown weight W shovm in the figures is supported by three cables, AB, AC, and AD. The tension in cable AB is 3 RN. a) Draw a complete and separate FBD for this system (5) b) Represent all the forces in rectangular vector form (10) 0) Write down the scalar equations needed to caiculate the weight of the crate (Do not solve) (5) d) Solve to find the weight of the crate. (5) Hint: Start with the summation of forces in the x direction .....__-=~ xx A f n “7“: I N» PH)?’ m r 2 L2 ~13”) ,,_ E12. [HO/h0_;‘1:¥\) WV“ Aifx‘mfwi“? M W M_Wms t? CK) :FYS-Q "E "f- ~l ~— 1" P r) p” 0 ® :Fj’l—Q) 6C) 4.. if? {a \\ - v—w- if N), 4—“- w W 13,-“ © 25w) —}_3; +3 1Q *Ei_i‘:© @ I? 15' far} ,1 a) Draw the free body diagram for the beam AB. (9) 2 pt for axes, lpt for each force and ooupie correctly shown b) Draw a free body diagram for beam AC. (8) i’roblem 4 (25 points) A machine component is subjected to the forces shown, each of which is parallel to one of the coordinate axes. y] a) Determine the moment of these four I mfg/1:"! forces about point B and express your 1.3a} 3‘: ,3 resuit in vector form (10) b) Repiace the four forces with a force and a couple at A and express your result in vector form. Draw a new 3%?6 for this. 90 mtr ‘ 0) Determine the scalar component of the w x moment in the direction AC (5) A ' z/KwiiLI/X/ ! f’, a) 0n H G N a} b Qua? ‘tLJt. iﬁé‘gw at}; 0 Prooivc'g mama/£5 CUL 5 M 63 m {gig W him» "L {Mg “’5‘ 53“) ® r r. . M @ rt '1’ v“ M rblg: ('OQJWIDL+/”IQ1}W m hit) :(KXQ , a” .4 \ ’ r Me “=— 00: ’L ’3 u ’1 g +0“ n. «~t we tz-é? hZooD O-Eoeo A O OINOO 1,00fDWooﬁ—{foookﬂ + .oojECv—IZOOI) 4580?};ng -_~_ (mol"+:3.tjmﬂ—lq Nm [2) b) gwstmwoﬂco _,, 72?sz 201251;} "a :g :3; 20- too : — zuoj +ZYL) N (a we (‘37 W ___. Wu“) H __, ' MA 3- rare-7“- t’m’ Mme F3013 ﬁre/e who; We WAN downs/“PAW”? M mom.th a?“ ((5/4 ‘2: “(fiat/A : (.03: +ID‘3J! "—- D}f§£)ﬁ1 "PD/A 160\$; +'OXJ'“th‘T)ﬁ:)I-M iJhE‘j ijkli EJKEJ .2» sheet 0 I; o or2+r~i§3rb Lf try “2’ +355 [1/10 "It’ll/t) 0 0—41)” oo \$000040“) 0 0 ,th 00 Wk; 1 (ﬁg-1500 ’YOOD "(’é‘mkﬂ wh OGYKWOO })—-(/5§mﬂj :1 «’SE —H’\$,§§' .4“? (a) Nm (2) _—_WW .._5 G: .... CU W («It +1} «am \w 20‘ "” 3v’?‘ ‘ W "\$WNM Q) [Ry f3 H QJS’Q O K \ 1ch F1» ...
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Fall 2008 Exam 2 Soln - ltz’ﬂrw Pa.”:03 TLSF’L...

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