15homework12 - Husain, Zeena Homework 12 Due: Nov 18 2003,...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Husain, Zeena Homework 12 Due: Nov 18 2003, 4:00 am Inst: H L Berk 1 This print-out should have 19 questions, check that it is complete. Multiple-choice questions may continue on the next column or page: find all choices before making your selection. The due time is Central time. 001 (part 1 of 2) 10 points The time interval indicated on this diagram is G . S G t S Which formula corresponds best to the di- agram? 1. S ( t ) = S sin 2 t 3 G 2. S ( t ) = S sin 3 t 2 G 3. S ( t ) = S sin 2 t 3 G 4. S ( t ) = S sin 2 t G 5. S ( t ) = S sin t 3 G 6. S ( t ) = S sin 3 t G correct 7. S ( t ) = S sin 2 t 3 G 8. S ( t ) = S sin 3 t 2 G 9. S ( t ) = S sin t 2 G 10. S ( t ) = S sin 3 t 2 G Explanation: The equation of a wave with zero displace- ment at the origin is given by S ( t ) = S sin( t ) = S sin 2 T t , since 2 T . From the figure, we see 1 3 G = 1 2 T which means T = 2 3 G . Since 2 T = 3 G , we have S ( t ) = S sin 3 G t . 002 (part 2 of 2) 10 points This wave has period T . S T t S Which formula corresponds best to the di- agram? 1. S ( t ) = S sin 2 t T- 2 2. S ( t ) = S sin 2 t T + 2 correct 3. S ( t ) = S sin t T- 2 4. S ( t ) = S sin t T + 2 5. S ( t ) = S sin 2- t T 6. S ( t ) = S sin t T 7. S ( t ) = S sin 2 t T 8. S ( t ) = S sin - 2- 2 t T 9. S ( t ) = S sin - 2 t T 10. S ( t ) = S sin - t T Explanation: First note that most of the incorrect solu- tions can be eliminated immediately by check- ing the value of the displacement at t = 0. The equation for a wave with period T and maximum displacement at the origin is S ( t ) = S cos 2 T t . Husain, Zeena Homework 12 Due: Nov 18 2003, 4:00 am Inst: H L Berk 2 Since cos( t ) = sin t + 2 we find S ( t ) = S sin 2 T t + 2 . 003 (part 1 of 5) 10 points The wave function for a linearly polarized wave on a taut string is y ( x,t ) = A sin( t- k x + ) , where A = 0 . 34 m, = 9 . 1 s- 1 , k = 6 . 2 m- 1 , = 0 . 41, t is in seconds and x and y are in meters. What is the speed of the wave? Correct answer: 1 . 46774 m / s. Explanation: Basic Concepts: v = T k = 2 f = 2 Solution: For the propagation speed of a wave we have v = k = (9 . 1 s- 1 ) (6 . 2 m- 1 ) = 1 . 46774 m / s . 004 (part 2 of 5) 10 points What is the vertical displacement of the string at x = 0 . 07 m, t = 3 s? Correct answer: 0 . 285793 m. Explanation: We can obtain the result if we simply sub- stitute the values for x and t into y ( x,t ) y ( x ,t ) = A sin[ t- k x + ] = (0 . 34 m) sin h (9 . 1 s- 1 ) (3 s)- (6 . 2 m- 1 ) (0 . 07 m) + (0 . 41) i = 0 . 285793 m ....
View Full Document

Page1 / 9

15homework12 - Husain, Zeena Homework 12 Due: Nov 18 2003,...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online