Kaplunovsky - hw 14 - homework 14 Due: May 2 2007, 4:00 am...

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homework 14 – – Due: May 2 2007, 4:00 am 1 Question 1, chap 16, sect 3. part 1 of 1 8 points You are given two waves, a transverse wave that moves to the right f 1 ( x ) and a transverse wave that moves to the left f 2 ( x ), on a string. As the problem begins, the wave f 1 ( x ) is mov- ing to the right at v 1 = +1 m/s and the wave f 2 ( x ) is moving to the left at v 2 = 1 m/s. v 1 v 2 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Amplitude (centimeter) Distance (meter) What is the shape of the wave on the string after 2 s? 1. 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Distance (meter) 2. 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Distance (meter) correct 3. 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Distance (meter) 4. 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Distance (meter) 5. 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Distance (meter) 6. 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Distance (meter)
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homework 14 – – Due: May 2 2007, 4:00 am 2 7. 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Distance (meter) 8. 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Distance (meter) 9. 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Distance (meter) 10. 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Distance (meter) Explanation: The initial wave moving to the right is rep- resented with a dashed line and the eave mov- ing to the left is represented with a dotted line. 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Amplitude (centimeter) Distance (meter) Initial time, t = 0 s After 2 s the positions of the two waves are have both moved 2 meters in opposite directions. The sum of the two wave is the resultant wave, the light gray line. 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Distance (meter) Superpostion, at t = 2 s 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Distance (meter) Resultant, at t = 2 s Question 2, chap 16, sect 3. part 1 of 1 8 points You are given two waves, a transverse wave that moves to the right f 1 ( x ) and a transverse
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homework 14 – – Due: May 2 2007, 4:00 am 3 wave that moves to the left f 2 ( x ), on a string. As the problem begins, the wave f 1 ( x ) is mov- ing to the right at v 1 = +1 m/s and the wave f 2 ( x ) is moving to the left at v 2 = 1 m/s. v 1 v 2 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Amplitude (centimeter) Distance (meter) What is the shape of the wave on the string after 3 s? 1. 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Distance (meter) 2. 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Distance (meter) 3. 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Distance (meter) 4. 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Distance (meter) correct 5. 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Distance (meter) 6. 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Distance (meter)
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homework 14 – – Due: May 2 2007, 4:00 am 4 7. 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Distance (meter) 8. 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Distance (meter) 9. 0 1 2 3 4 5 6 7 8 9 10 -3 -2 -1 0 1 2 3 Distance (meter) 10. 0
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This note was uploaded on 01/29/2009 for the course PHY 303K taught by Professor Turner during the Spring '08 term at University of Texas at Austin.

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Kaplunovsky - hw 14 - homework 14 Due: May 2 2007, 4:00 am...

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