Kaplunovsky - practice 14

Kaplunovsky - practice 14 - practice 14 Due: Apr 30 2007,...

Info iconThis preview shows pages 1–5. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: practice 14 Due: Apr 30 2007, noon 1 Question 1, chap 16, sect 3. part 1 of 1 8 points You are given two waves, a transverse wave that moves to the right f 1 ( x ) and a transverse wave that moves to the left f 2 ( x ), on a string. As the problem begins, the wave f 1 ( x ) is mov- ing to the right at v 1 = +1 m/s and the wave f 2 ( x ) is moving to the left at v 2 = 1 m/s. v 1 v 2 1 2 3 4 5 6 7 8 9 10-3-2-1 1 2 3 Amplitude(centimeter) Distance (meter) What is the shape of the wave on the string after 2 . 5 s? 1. 1 2 3 4 5 6 7 8 9 10-3-2-1 1 2 3 Distance (meter) 2. 1 2 3 4 5 6 7 8 9 10-3-2-1 1 2 3 Distance (meter) 3. 1 2 3 4 5 6 7 8 9 10-3-2-1 1 2 3 Distance (meter) 4. 1 2 3 4 5 6 7 8 9 10-3-2-1 1 2 3 Distance (meter) 5. 1 2 3 4 5 6 7 8 9 10-3-2-1 1 2 3 Distance (meter) 6. 1 2 3 4 5 6 7 8 9 10-3-2-1 1 2 3 Distance (meter) correct practice 14 Due: Apr 30 2007, noon 2 7. 1 2 3 4 5 6 7 8 9 10-3-2-1 1 2 3 Distance (meter) 8. 1 2 3 4 5 6 7 8 9 10-3-2-1 1 2 3 Distance (meter) 9. 1 2 3 4 5 6 7 8 9 10-3-2-1 1 2 3 Distance (meter) 10. 1 2 3 4 5 6 7 8 9 10-3-2-1 1 2 3 Distance (meter) Explanation: The initial wave moving to the right is rep- resented with a dashed line and the eave mov- ing to the left is represented with a dotted line. 1 2 3 4 5 6 7 8 9 10-3-2-1 1 2 3 Amplitude(centimeter) Distance (meter) Initial time, t = 0 s After 2 . 5 s the positions of the two waves are have both moved 2 . 5 meters in opposite directions. The sum of the two wave is the resultant wave, the light gray line. 1 2 3 4 5 6 7 8 9 10-3-2-1 1 2 3 Amplitude(centimeter) Distance (meter) Superpostion, at t = 2 . 5 s 1 2 3 4 5 6 7 8 9 10-3-2-1 1 2 3 Amplitude(centimeter) Distance (meter) Resultant, at t = 2 . 5 s Question 2, chap 16, sect 3. part 1 of 1 8 points You are given two waves, a transverse wave that moves to the right f 1 ( x ) and a transverse practice 14 Due: Apr 30 2007, noon 3 wave that moves to the left f 2 ( x ), on a string. As the problem begins, the wave f 1 ( x ) is mov- ing to the right at v 1 = +1 m/s and the wave f 2 ( x ) is moving to the left at v 2 = 1 m/s. v 1 v 2 1 2 3 4 5 6 7 8 9 10-3-2-1 1 2 3 Amplitude(centimeter) Distance (meter) What is the shape of the wave on the string after 3 s? 1. 1 2 3 4 5 6 7 8 9 10-3-2-1 1 2 3 Distance (meter) 2. 1 2 3 4 5 6 7 8 9 10-3-2-1 1 2 3 Distance (meter) 3. 1 2 3 4 5 6 7 8 9 10-3-2-1 1 2 3 Distance (meter) 4. 1 2 3 4 5 6 7 8 9 10-3-2-1 1 2 3 Distance (meter) 5. 1 2 3 4 5 6 7 8 9 10-3-2-1 1 2 3 Distance (meter) 6. 1 2 3 4 5 6 7 8 9 10-3-2-1 1 2 3 Distance (meter) practice 14 Due: Apr 30 2007, noon 4 7. 1 2 3 4 5 6 7 8 9 10-3-2-1 1 2 3 Distance (meter) 8. 1 2 3 4 5 6 7 8 9 10-3-2-1 1 2 3 Distance (meter) 9....
View Full Document

This note was uploaded on 01/29/2009 for the course PHY 303K taught by Professor Turner during the Spring '08 term at University of Texas at Austin.

Page1 / 14

Kaplunovsky - practice 14 - practice 14 Due: Apr 30 2007,...

This preview shows document pages 1 - 5. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online