SOLUCION ALGEBRAICAMENTE.docx - SOLUCION ANALITICA: o...

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SOLUCION ANALITICA:oDatos:ρA=1050kgm3, ρB=875kgm310m3hde A ,10m3hde BoSolución:Hallaremos el volumen del líquido del recipiente para 25 minutos:20m360min(25min)=8.333m3Entonces el volumen del recipiente será:8.333m3=23Vrec.Vrec.=24.9992m3Vrec.=12.50m3Procedemos a hallar H, utilizando la formula del cilindro.Sabemos que D = HV=π D2. H4entonces seriaV=π D2. D4V=π D2. D412.50m3=π D2. D415.915=D3D=H=2.515mA continuación, hallaremos las alturas para los niveles de A y B:
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Term
Summer
Professor
A. Guerrro
Tags
Volumen, Kilogramo, Recipiente, 1050 10 kg, 875 3 3 m

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