lab_08 - Lab 08 December 5 2006 A linear model using the...

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Unformatted text preview: Lab 08 December 5, 2006 A linear model using the equation, Y = a + b * x, was used so that we could construct a best fit model. Threshold #1:- r =-0.8437- a =10.5311- b =-1.1498- MSE = 4.2378 This linear model shows the highest mean squared error, therefore, it is the worst fit for this data. Threshold #2:- MSE = 2.7974 In this second data set, the high mean squared error of the thresholds confirms that this model is not the best fit for this data. 1 2 3 4 5 6 7 8 9 10-2 2 4 6 8 10 12 14 16 X Y Linear Model of Thresholds (Y) vs. Time Elapsed in Minutes (X) This is the second scenario, as we show that an exponential model (Y=c*exp(-d*X)) was used to create a best fit model. Threshold #1:- r =-0.8437- c =19.9199- d =0.3808- MSE = 0.9054 The exponential model shows the second highest mean squared error, therefore, we cannot acknowledge this model as the best fitting model for the data. Threshold #2:- MSE = 0.8020 In the second data set, the mean squared error of the thresholds confirms that this model is not the...
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lab_08 - Lab 08 December 5 2006 A linear model using the...

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