# Chapter 5 Edited Fall 2012 - Elements that exist as gases...

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Elements that exist as gases at 250C and 1 atmosphere
Gases assume the volume and shape of their containers.Gases are the most compressible state of matter.Gases will mix evenly and completely when confined to the same container.Gases have much lower densities than liquids and solids.Physical Characteristics of Gases
Sea level1 atm4 miles0.5 atm10 miles0.2 atm
Manometers Used to Measure Gas Pressures
P1V1= P2V2n1T1n2T2
A sample of chlorine gas occupies a volume of 946 mL at a pressure of 726 mmHg. What is the pressure of the gas (in mmHg) if the volume is reduced at constant temperature to 154 mL?V212
A sample of carbon monoxide gas occupies 3.20 L at 125 0C. At what temperature will the gas occupy a volume of 1.54 L if the pressure remains constant?11T2
3 atm + 1 atm 2 atm
Ammonia burns in oxygen to form nitric oxide (NO) and water vapor. How many volumes of NO are obtained from one volume of ammonia at the same temperature and pressure?4NH3+ 5O24NO + 6H2O1 mole NH31 mole NOAt constant Tand P1 volume NH31 volume NO
What is the volume (in liters) occupied by 49.8 g of HCl at STP?
P
Argon is an inert gas used in lightbulbs to retard the vaporization of the filament. A certain lightbulb containing argon at 1.20 atm and 18 0C is heated to 85 0C at constant volume. What is the final pressure of argon in the lightbulb (in atm)?
2
EMGP 4. A 54.2 g sample of MgSO4xH2O is heated to 120°C in a closed evacuated 2.00 L container. The resulting water vapor exerts a pressure of 24.8 atm in the container. Calculate x.
A 2.10-L vessel contains 4.65 g of a gas at 1.00 atm and 27.0 0C. What is the molar mass of the gas?
EMGP 5. An oxide of nitrogen has a density of 1.33 g/L measured at 764 torr and 150°C. What is the likely formula of the oxide?
Gas StoichiometryWhat is the volume of CO2produced at 37 0C and 1.00 atm when 5.60 g of glucose are used up in the reaction:C6H12O6(s) + 6O2(g) 6CO2(g) + 6H2O (l)g C6H12O6mol C6H12O6mol CO2VCO25.60 g C6H12O61 mol C6H12O6180 g C6H12O6x6 mol CO21 mol C6H12O6x= 0.187 mol CO2V= nRTP0.187 mol x 0.0821 x 310.15 KL•atmmol•K1.00 atm== 4.76 L