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Homework2 - Version 212 Homework 2 Sutcliffe(53980 This...

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Version 212 – Homework 2 – Sutcliffe – (53980) 1 This print-out should have 17 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. Solubility Rules can be seen in Table 5.9 in your book or you may download a pdf from Blackboard, under COurse Documnents, Useful Items. NOTE FOR Q9: We’re looking for the most commonly used steps, but they might not be listed in the order they are done. 001 10.0 points Use electron-dot notation to demonstrate the formation of an ionic compound involving the elements Na and S. 1. Na + S -→ Na + + S -→ NaS 2. Na + Na + Na + S -→ Na + + Na + + Na + + S 3 -→ Na 3 S 3. Na + S -→ Na 3+ + S 3 -→ NaS 4. Na + Na + S + S + S -→ Na 3+ +Na 3+ + S 2 + S 2 + S 2 -→ Na 2 S 3 5. Na + S + S -→ Na 2+ + S + S -→ NaS 2 6. Na + S -→ Na 2+ + S 2 -→ NaS 7. Na + Na + Na + S + S -→ Na 2+ + Na 2+ + Na 2+ + S 3 + S 3 -→ Na 3 S 2 8. Na + Na + S -→ Na + + Na + + S 2 -→ Na 2 S correct 9. Na + S + S + S -→ Na 3+ + S + S + S -→ Na 2 S 3 10. None of these Explanation: Na gives up an electron to form the Na + cation and S acquires two electrons to form the S 2 anion: Na + Na + S -→ Na + + Na + + S 2 -→ Na 2 S 002 10.0 points SO 2 4 is more/less polar than SO 2 3 because 1. less; the four polar S O bonds in SO 2 4 are symmetrical and cancel the dipole moments. correct 2. more; the four polar S O bonds in SO 2 4 are arranged non-symmetrically leaving a net dipole moment. 3. more; it has four polar S O bonds rather than three polar S O bonds. 4. less; it is a resonance structure. 5. more; the tetrahedral geometry increases the polarity of S O bonds Explanation: SO 2 4 has no lone pairs on the central S atom. It has tetrahedral molecular geometry. Each bond angle is 109.5 . The dipole mo-
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Version 212 – Homework 2 – Sutcliffe – (53980) 2 ments cancel and the molecule is non-polar. SO 2 3 has one lone pair on the central S atom. It has pyramidal molecular geometry. The bond angles are not equal so the dipole moments cannot cancel. This molecule is polar.
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