Exam 1 Solutions - Exam 1 So‘ufioms 1 B7 de—fmkiom...

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Unformatted text preview: Exam 1 So‘ufioms 1. B7 de—fmkiom 0‘} {403/ Keir/(D) <2) fiveD. FM” a"; X6 VCD‘MVLDQ , +Lew X61970) and’ ”My Heme $0961). avdl ¥cx)ebz _ Tba—Qp‘s/ hue-DMD; Mum b7 ole-FM-Uov; 05 {"cw/ xe{"( D‘flDz) ““25th MM 3” f"tb.>n¥"(\>z) gig, ‘m {Yuan}; 5° 1“"(Dorw‘tm s. {mummy 2. We. Prove, b7 COM{Ta0l§c~&g‘oh‘ SuYrOSe A :3 uncoun‘Eablf" B is cowfimble/ OUWQ /~\\5 15 caunkcyfl. Ame Jaws /-\= CAnB>UL/~\\£3>. MB :5 a May; 07L 4 Comma 5.94; B. ByTth, ARE :5 CoqumL\e_ Them 107 fie TLM ‘m +l—e fieOYW fleet we We" 9+ 4WD away: 56E; 25 comeb/e. chfl LAGBDUCAV5) (5 CoMW‘aCtLle' ‘TLu‘s Mews A Rs cawwble ,eow—Lmahdm‘hj We Comp/£90»: H44: /-\ 1S U“CM¥Q5‘€. Wemfoye Afi MuSQ be; UM Co un‘kab}€ ‘ (a) 3. 98n0a X>o, Ho. 97 M5, 3? egg“ my? 750%“. B7 01, 3? ‘6 BMW (60 =0 or L10) «9/ orcc) >0 I C“) /\S§uwv: = 0. Then X" \ ‘; . 7%‘X20‘X. 67 lV‘}. ”k‘fl‘fi? chat 0X XO 50 X‘fif-tX'O’ By N5, x-~}-(~=\. ‘57 Twn-rw, X~o=o 5° We have. 120 Tm; Comirad€c£s M4 : IaiO. Hence 4)? 1‘- 0 U0) A59uwve, *{0 Tiren b); TLMH'I C-F) 41mm X>0 We have 3.4;? 40“? By M5] XW/IT“ 57 ThmlLHb), fir-o =0 50 WE hon/6 1 < 0‘ 17>qu Jake” fifucc, x>o, by 04-, 1‘X<0‘>< 97 (”2/ 1‘X-><\\ ad o-X = ><~o 57 MS, KW: X owl b7 TL‘MH.ICL)/ X-O=O 50 We. have, 7f<0 , Coukr‘aphds ”the comJi—éfou X>c9, Hence L19) 0’095 mo-E Mal. wpwqm on!) cc) Lows: 340-0 . x.“ For 0w: X G S / Xé /‘\‘VD $0)” Suva ”3'0 QN. Swat /‘\;0 is Ofevr, 307 Hum 15.7m) , xemfi A” . Heat/e fLere, exsfj a £>o such ‘Hm-E Must) 9AM 8ch ALOCS $0 Nagass. T1404; {9/ KeM’ES. scflce, each Poiwt 05 5 :5 an Mfeh‘cr‘ Fem-L 0% 3/ by TLM [37(001 8 I5 cfem. 5Ufl7ose xe Mb? ad x is m4; ow acoumulaiu‘w Fem. We show Jvhfi x {5 an §50\a£eoQ yohan of 5. T1“; is egu‘welwk £0 show x e fivtfiu‘nte anj Pow .‘n S is €{Jduer‘ an accuwtmfl’ Penal; or an .‘sbka—ted Pt ) SQFFOSQ X ¢ 5 . 5"Kfe /< f5 WO‘E am accumula'ENV‘ PJ‘/ ‘tLere {5 0m 2°>o si, “(55%)05 : qfl 8qu Sl‘uc-e K4 5, /\/(x)' £005 2 (b ‘ Tins Codraofiék +1/Q Cow0€.'£t'0n 471ml: Kebié. Tierefarp. 2< mu5{ be ‘m 9 0M K (9 an i'Solm‘QCOQ PJ‘ 0* 5. 50 ,‘L 15 CM “We” boom/Q 0.3 S, \”> For anj MGR 5.1:. M<1/ “We" ‘~M>O‘ 5/ AP, €x€9~ts woe/N 9AM o< AVG <1»M or \“__L > M 5"an §= 1“?) éfi and 67”“ / M L5 "0 . 0 M03: cm urfb‘ 190ou 0-K 3. 0) dupe \“U Pam/E 1L: suFLS. (L) 0'3: l—-‘;; 6 6, Hence 3%? “"3 {9’0 / NLM‘; z)(\§ #45. For 0143 7,70 , by Thu/112.14, txvs’tg Vé R\®\ 5.1L. 0.3 <r 4 o.&+ 2. Hence VG NCO'S’)€) any? T6 R\$ . T‘l-eveffore NLO.S)£)m K\3 #613. By c§e§twigrom I 0.3 ébugé. LC) Ms = $ui13, each $63 13 an {Sch—Ltd POIW‘fi/ cwa i \5 cm C(CouwwthCOt/t FQM£ 0% 6 , H€I4<€ hoof)”— SUéj; ad) msnp 5mm: 5g 1046. 3% 3’: mg Fov 6M5 8>O / [07 AP/ eszés MGM §.£« \ 0<fi<i/ of L>l«—L—‘>l~2 ‘50 l-fieA/a‘é13é) 6&on (wk 63. Kg) 5 {5 Ho{ bfen fit‘ptCQ (VI-{3:45 #S s a) my: exogeaz sew: Ms =5ui13 i 5- ...
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