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Unformatted text preview: Hou, Taylor Homework 10 Due: Dec 7 2007, 11:00 pm Inst: Brodbelt 1 This print-out should have 15 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. The due time is Central time. Brodbelt CH301 HW 10 Due December 7, 11:00 pm 001 (part 1 of 1) 10 points You cant unscramble an egg might be a laymans view of 1. the third law of thermodynamics. 2. the first law of thermodynamics. 3. the woeful lament of a student contem- plating checking his work on an exam. 4. the second law of thermodynamics. cor- rect Explanation: The Second Law of Thermodynamics states that in spontaneous changes the universe tends toward a state of greater disorder. 002 (part 1 of 1) 10 points Which substance has the higher molar en- tropy? 1. Unable to determine 2. KCl(aq) at 298 K and 1.00 atm correct 3. KCl(s) at 298 K and 1.00 atm 4. They are the same Explanation: KCl(aq) has ions distributed more ran- domly in solution than ions localized in a crystal lattice, hence a higher molar entropy. 003 (part 1 of 1) 10 points Without performing any calculations, de- termine whether the entropy of the system increases or decreases in Cu 3 (PO 4 ) 2 (s) 3Cu 2+ (aq) + 2PO 3- 4 (aq) 1. increases correct 2. decreases 3. Unable to determine 4. The entropy does not change. Explanation: Entropy should increase because the dis- solution of the solid copper phosphate will increase the randomness of the copper and phosphate ions. 004 (part 1 of 1) 10 points The temperature of 2.00 mol Ne(g) is in- creased from 25 C to 200 C at constant pres- sure. Assume the heat capacity of Ne is 20.8 J/K-mol. Calculate the change in the entropy of neon. Assume ideal behavior. 1. +19.2 J K- 1 correct 2. +7.68 J K- 1 3.- 19.2 J K- 1 4. +9.60 J K- 1 5.- 7.68 J K- 1 Explanation: 005 (part 1 of 1) 10 points Consider the following processes. (Treat all gases as ideal.) I) The pressure of one mole of oxygen gas is allowed to double isothermally.is allowed to double isothermally....
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- Spring '07