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math171 lab8 3-27-08

math171 lab8 3-27-08 - than the actual jump The model...

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Lab 8 2. There is a positive trend The biggest gap is between 1936 and 1948, because of World War II. 1972 is a high outlier, 1896 a low outlier. 4.
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5. I chose every point after 1950, excepting 1972, because there was a gap in data between 1936 and 1948, and because the 1972 value was much higher than the trend for every other year. My model works well, it has an R 2 value of 0.86, which is reasonably high, and the regression line fits the data. y = 0.8465 x + 263.6 The slope is the average increase in length of the winning jump with each yearly increase. The R-Squared value is the percentage to which the regression line fits the data, thus the accuracy of the trend line. The model predicts y = 0.8465(100) + 263.6 = 348.3, which was 11.7 inches more
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Unformatted text preview: than the actual jump. The model overestimated the actual result. • The model predicts y = 0.8465(104) + 263.6 = 351.6, which was 13.4 inches more than the actual jump. The model still overestimated the actual result. • The model predicts y = 0.8465(108) + 263.6 = 355.0 inches, which, considering the results from the last two predictions above, will probably be more than the actual jump distance. Going with the trend from the last predictions, this calculation will probably be about 15 inches more than the actual distance. • The model predicts y = 0.8465(200) + 263.6 = 432.9 inches, which does not sound reasonable, considering it would beat the (relatively current) 2004 gold medal distance by almost 8 feet....
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