practice1 - Granillo, Yvette Review 1 Due: Dec 9 2005, 6:00...

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Unformatted text preview: Granillo, Yvette Review 1 Due: Dec 9 2005, 6:00 pm Inst: Edward Odell 1 This print-out should have 19 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. The due time is Central time. Review one covers the material on test 1, namely it covers sections 2.1-2.3,2.5,2.6,3.1- 3.4. While you can submit answers and get a score as usual this counts 0 001 (part 1 of 1) 10 points After t seconds the displacement, s ( t ), of a particle moving rightwards along the x-axis is given (in feet) by s ( t ) = 5 t 2- 8 t + 6 . Determine the average velocity of the particle over the time interval [1 , 3]. 1. average vel. = 11 ft/sec 2. average vel. = 9 ft/sec 3. average vel. = 12 ft/sec correct 4. average vel. = 8 ft/sec 5. average vel. = 10 ft/sec Explanation: The average velocity over a time interval [ a, b ] is given by dist travelled time taken = s ( b )- s ( a ) b- a . For the time interval [1 , 3], therefore, ave. vel. = s (3)- s (1) 3- 1 ft/sec . Now s (3) = 5 9- 8 3 + 6 = 27 feet , while s (1) = 5- 8 + 6 = 3 feet . Consequently, avg. vel. = 27- 3 2 = 12 ft/sec . keywords: Stewart5e, 002 (part 1 of 1) 10 points Below is the graph of a function y = f ( x ) 2 4 6- 2- 4- 6 2 4 6 8- 2- 4 Use the graph to determine the right hand limit lim x 1+ f ( x ) . 1. lim x 1+ f ( x ) = 0 correct 2. lim x 1+ f ( x ) =- 4 3. lim x 1+ f ( x ) = 6 4. lim x 1+ f ( x ) = 3 5. the limit does not exist Explanation: From the graph lim x 1+ f ( x ) = 0. keywords: Stewart5e, Granillo, Yvette Review 1 Due: Dec 9 2005, 6:00 pm Inst: Edward Odell 2 003 (part 1 of 1) 10 points A function f is defined piecewise for all x 6 = 0 by f ( x ) = 4 + x, x <- 2 , 5 2 x, < | x | 2 , 5 + x- 1 2 x 2 , x > 2 . By first drawing the graph of f , determine all the values of a at which lim x a f ( x ) exists, expressing your answer in interval no- tation. 1. (- , 0) (0 , ) 2. (- , 2) (2 , ) 3. (- ,- 2) (- 2 , 0) (0 , ) 4. (- ,- 2) (- 2 , ) correct 5. (- , 0) (0 , 2) (2 , ) 6. (- ,- 2) (- 2 , 2) (2 , ) 7. (- ,- 2) (- 2 , 0) (0 , 2) (2 , ) Explanation: The graph of f is 2 4- 2- 4 2 4- 2- 4 and inspection shows that lim x a f ( x ) will exist only for a in (- ,- 2) (- 2 , ) . keywords: Stewart5e, 004 (part 1 of 1) 10 points Evaluate lim x x 6 + 5 x 3 4 x 8 + 7 x 11 . 1. limit =- 2. limit = 5 3. limit = 0 4. none of these correct 5. limit = + Explanation: Since x 6 + 5 x 3 4 x 8 + 7 x 11 = x 3 + 5 x 5 (4 + 7 x 3 ) , we see that none of 5 , + , ,- can be the limit because x 3 + 5 x 5 (4 + 7 x 3 )- + as x 0+, while x 3 + 5 x 5 (4 + 7 x 3 )- - as x - . Consequently, none of these is the correct answer. Granillo, Yvette Review 1 Due: Dec 9 2005, 6:00 pm Inst: Edward Odell 3 keywords: Stewart5e, limit, infinite limit, ra-...
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practice1 - Granillo, Yvette Review 1 Due: Dec 9 2005, 6:00...

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