ANT1Lecture3

ANT1Lecture3 - Discussion Sections Social Sciences 233...

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Unformatted text preview: Discussion Sections Social Sciences 233 Essay Assignment #1 ‣ 3 Handouts on website ‣ Due in 2 weeks during discussion sections ‣ January 29, 30, or 31 Anthropology 1 – Winter 2008 Human Evolutionary Biology Tall Short A 1 A 2 Genotype Blending Inheritance Phenotype Blending Inheritance Gamete A 2 A 1 A 3 = (A 1 + A 2 ) / 2 1. Tall mates only with short Gamete A 3 A 3 A 3 2. Random mating Tall Short A 1 A 1 A 2 A 2 Genotype Mendelian Inheritance Phenotype Tall Short Mendelian Inheritance A 1 A 1 A 2 A 2 Tall Short Mendelian Inheritance A 1 A 1 A 2 A 2 A 1 A 1 Tall Short Mendelian Inheritance A 1 A 1 A 2 A 2 A 1 A 1 A 2 A 2 Mendelian Inheritance Gamete A 2 A 1 A 1 A 2 1. Tall mates only with short Intermediate Mendelian Inheritance A 1 A 2 Intermediate Mendelian Inheritance A 1 A 2 A 1 A 2 Mendelian Inheritance Gamete A 1 A 2 A 1 A 1 A 1 A 1 A 2 A 2 A 2 A 1 A 2 A 2 2. Random mating Census of a Hypothetical Population Genotype Number Frequency aa 2,000 .2 Aa 4,000 .4 AA 4,000 .4 10,000 1.0 Adults (AA, Aa, aa) Gametes (A, a) Zygotes (AA, Aa, aa) Meiosis Sex ‣ Assume individuals mate at random 1. Compute frequency of alleles in gametes 2. Compute chance a given pair of alleles meet 3. Compute frequency of alleles in next generation Adults (AA, Aa, aa) Gametes (A, a) Zygotes (AA, Aa, aa) Meiosis Sex #1 ‣ Assume individuals mate at random 1. Compute frequency of alleles in gametes 2. Compute chance a given pair of alleles meet 3. Compute frequency of alleles in next generation Step 1: Meiosis Each gamete has only one allele from the locus a Step 1: Meiosis Each gamete has only one allele from the locus a Step 1: Meiosis –so– Each gamete has only one allele from the locus a Step 1: Meiosis (# a gametes per aa parent) × (# aa parents) + (# a gametes per Aa parent) × (# Aa parents) Step 1: Meiosis (# a gametes per aa parent) × (# aa parents) + (# a gametes per Aa parent) × (# Aa parents) (# gametes per parent) × (# of parents) Step 1: Meiosis Step 1: Meiosis (# a gametes per aa parent) × (# aa parents) + (# a gametes per Aa parent) × (# Aa parents) (# gametes per parent) × (# of parents) Genotype Number Frequency aa 2,000 .2 Aa 4,000 .4 AA 4,000 .4 10,000 1.0 Step 1: Meiosis (# a gametes per aa parent) × (# aa parents) + (# a gametes per Aa parent) × (# Aa parents) (# gametes per parent) × (# of parents) 2 x 2,000 + Genotype Number Frequency aa 2,000 .2 Aa 4,000 .4 AA 4,000 .4 10,000 1.0 Step 1: Meiosis...
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ANT1Lecture3 - Discussion Sections Social Sciences 233...

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