# HWK9 - Valenica, Daniel Homework 9 Due: Oct 30 2007, 3:00...

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Unformatted text preview: Valenica, Daniel Homework 9 Due: Oct 30 2007, 3:00 am Inst: Cheng 1 This print-out should have 15 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. The due time is Central time. 001 (part 1 of 1) 10 points Evaluate the iterated integral I = Z 4 1 n Z 4 1 ( x + y ) 2 dx o dy . 1. I = ln 5 2 correct 2. I = 2 ln 12 7 3. I = 2 ln 5 2 4. I = 1 2 ln 5 2 5. I = ln 12 7 6. I = 1 2 ln 12 7 Explanation: Integrating the inner integral with respect to x keeping y fixed, we see that Z 4 1 ( x + y ) 2 dx = h- 1 x + y i 4 = n 1 y- 1 4 + y o . In this case I = Z 4 1 n 1 y- 1 4 + y o dy = h ln y- ln(4 + y ) i 4 1 . Consequently, I = ln (4)(1 + 4) (4 + 4) = ln 5 2 . keywords: iterated integral, rational function, log integral 002 (part 1 of 1) 10 points Evaluate the iterated integral I = Z ln 5 Z ln 4 e 2 x- y dx ! dy . 1. I = 4 2. I = 5 3. I = 6 correct 4. I = 7 5. I = 8 Explanation: Integrating with respect to x with y fixed, we see that Z ln 4 e 2 x- y dx = 1 2 h e 2 x- y i ln 4 = 1 2 e 2 ln 4- y- e- y = 4 2- 1 2 e- y . Thus I = 15 2 Z ln 5 e- y dy =- 15 2 h e- y i ln 5 =- 15 2 e- ln 5- 1 . Consequently, I =- 15 2 1 5- 1 = 6 . keywords: 003 (part 1 of 1) 10 points Valenica, Daniel Homework 9 Due: Oct 30 2007, 3:00 am Inst: Cheng 2 Determine the value of the double integral I = Z Z A 3 xy 2 9 + x 2 dA over the rectangle A = n ( x, y ) : 0 x 2 ,- 4 y 4 o , integrating first with respect to y . 1. I = 32 ln 13 9 2. I = 64 ln 13 18 3. I = 64 ln 9 13 4. I = 64 ln 13 9 correct 5. I = 32 ln 13 18 6. I = 32 ln 9 13 Explanation: The double integral over the rectangle A can be represented as the iterated integral I = Z 2 Z 4- 4 3 xy 2 9 + x 2 dy dx , integrating first with respect to y . Now after integration with respect to y with x fixed, we see that Z 4- 4 3 xy 2 9 + x 2 dy = h xy 3 9 + x 2 i 4- 4 = 128 x 9 + x 2 . But Z 2 128 x 9 + x 2 dx = h 64 ln(9 + x 2 ) i 2 . Consequently, I = 64 ln 13 9 . keywords: 004 (part 1 of 1) 10 points Evaluate the integral, I , of the function f ( x, y ) = 2 xe xy over the rectangle A = { ( x, y ) : 0 x 3 , y 3 } . 1. I = 1 3 e 9- 8 2. I = 1 3 e 9- 10 3. I = 1 3 e 9- 9 4. I = 2 3 e 9- 8 5. I = 2 3 e 9- 10 correct 6. I = 2 3 e 9- 9 Explanation: The integral is given by I = Z Z A 2 xe xy dxdy. Since the integral with respect to y can be evaluated easily using substitution (or di- rectly making the substitution in ones head), while the integral with respect to x requires integration by parts, this suggests that we should represent the double integral as the repeated integral I = Z...
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## This homework help was uploaded on 04/16/2008 for the course CALC 303L taught by Professor Cheng during the Fall '07 term at University of Texas at Austin.

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HWK9 - Valenica, Daniel Homework 9 Due: Oct 30 2007, 3:00...

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