hw7_soultion

# hw7_soultion - Chapter 4 Problem 24 Use source...

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1 Chapter 4, Problem 24. Use source transformation to find the voltage V x in the circuit of Fig. 4.92. Figure 4.92 For Prob. 4.24. Solution. Transform the two current sources in parallel with the resistors into their voltage source equivalents yield, a 30-V source in series with a 10- resistor and a 20V x -V sources in series with a 10- resistor. We now have the following circuit, We now write the following mesh equation and constraint equation which will lead to a solution for V x , 28I – 70 + 20V x = 0 or 28I + 20V x = 70, but V x = 8I which leads to 28I + 160I = 70 or I = 0.3723 A or V x = 2.978 V . + 8 10 10 3 A 40 V + V x 2 V x I 8 10 10 + _ 40 V + V x + 20V x –±+ 30 V

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2 Chapter 4, Problem 26. Use source transformation to find i o in the circuit of Fig. 4.94. Figure 4.94 For Prob. 4.26. Solution. Transforming the current sources gives the circuit below. –12 + 11i o –15 +20 = 0 or 11i o = 7 or i o = 636.4 mA . + _ 2 5 4 3 A 6 A i o 20 V + _ i o 20 V + 2 15 V 5 4 + _ 12 V
3 Chapter 4, Problem 28.

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hw7_soultion - Chapter 4 Problem 24 Use source...

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