EE 207 Homework - 15 = 15 b 15 25 = 40 Ω Ω Ω c 30 50 =...

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Haifa Altamimi #131372 Dr. Sghaier Guizani October 21 st , 2014 EE 207 Homework #2 Chapter 2 1. Problem 2.30: Find R eq for the circuit in Fig. 2.94. The 180 and 60 are in series. Therefore: Ω Ω R eq 1 = 180+60 = 240 Now the 240 and 60 are in parallel, so: Ω Ω 1 240 + 1 60 = 1 48 = ¿ R eq 2 = 48. Remaining is the 25 and 48 , which are in series=> 25+48= Ω Ω R eq = 73 Ω 2. Problem 2.36: Find i and V 0 in the circuit of Fig. 2.100 a) We combine the 60 and 20 : Ω Ω 1 60 + 1 20 = 1 15 = ¿
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Unformatted text preview: 15 = ¿ 15 b) 15 + 25 = 40 Ω Ω Ω c) 30 +50 = 80 Ω Ω Ω d) 1 80 + 1 20 = 1 16 = ¿ 16 e) 16 Ω + 24 Ω = 40 Ω f) 1 40 + 1 40 = 1 20 = ¿ 20 g) R eq = 20 + 80 = 100 i= V R eq = 20 100 = 0.2 A a = ¿ V ¿ 30 i i 1 = 40 40 + 40 i = 0.1 A i = 20 20 + 80 i 1 = 0.02 A a = ¿ V ¿ 30(0.02) = 0.6V 3. Problem 2.48 a) Convert the circuits in Fig. 2.112 from Y to ∆ 2 [Type text]...
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