ISE361_HW2answers_F03 - Homework Two Fall 2003 2. a) Event...

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Homework Two Fall 2003 2. a) Event A = {RRR, LLL, SSS} c) Event C = {RRL, RRS, RLR, RSR, LRR, SRR} d) Event D = {RRL, RRS, RLR, RSR, LRR, SRR, LLR, LLS, LRL, LSL, RLL, SLL, SSR, SSL, SRS, SLS, RSS, LSS} e) Event D’ contains outcomes where all cars go the same direction, or they all go different directions. D’ ={RRR, LLL, SSS, RLS, RSL, LRS, LSR, SRL, SLR} Event D totally encloses Event C, the compound event CUD = D; CUD = {RRL, RRS, RLR, RSR, LRR, SRR, LLR, LLS, LRL, LSL, RLL, SLL, SSR, SSL, SRS, SLS, RSS, LSS} C intersect D = C = {RRL, RRS, RLR, RSR, LRR, SRR} 12. a) P(A U B) = .50 + .40 - .25 = .65 b) P(A U B) = 1 - .65 = .35 c) A intersect B’; P(A intersect B’) = P(A) – P(A intersect B) = .50 - .25 = .25 16. a) There are six events, corresponding to the outcomes CDP, CPD, DCP, DPC, PCD, & PDC. The probability assigned to each is 1/6. b) P(C ranked first) = P({CPD,CDP}) = 1/6 + 1/6 = 2/6 = .333 18. This situation requires the complement concept. The only way for the desired event NOT to happen is if a 75 W bulb is selected first. Let event A be that a 75 W bulb is selected first, and P(A) = 6/15. Then the desired event is event A’.

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This homework help was uploaded on 04/16/2008 for the course ISE 361 taught by Professor Koon during the Spring '08 term at Binghamton University.

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ISE361_HW2answers_F03 - Homework Two Fall 2003 2. a) Event...

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