Homework Seven
Chapter 8
Dec/2001
6)
H
0
:
u
= 40 vs
H
a
:
u
= 40, where
u
is the true average burnout amperage for this
type of fuse.
The alternative reflects the fact that a departure from
u
= 40 in either
direction is of concern.
Notice that in this formulation, it is initially believed that the
value of
u
is the design value of 40.
20)
With
H
0
:
u
= 750, and
H
a
:
u
< 750 and a significance level of .05, we reject
H
0
if
z <  1.645; z = 2.14 < 1.645, so we reject the null hypothesis and do not continue
with the purchase.
At a significance level of .01, we reject
H
0
if z < 2.33;
z = 2.14 > 2.33, so we don’t reject the null hypothesis and thus continue with the
purchase.
24)
H
0
:
u
= 3,000 vs
H
a
:
u
= 3,000 ;
t
= (x – 3,000)/ (s/ (n)
1/2
) ; reject
H
0
if

t
 >
t
.025, 4
= 2.776 ;
t
= (2,887.6 – 3,000) / 84/(5)
1/2
= 2.99 < 2.776, so we reject
H
0
.
This requirement is not satisfied.
25)
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 Spring '08
 Koon
 Statistical hypothesis testing, H0, vs ha

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