Exam 1-solutions - 139 version number signature Yasmeen Zubair(ykz57 EXAM 1 Sparks Class(50155 Water Data Kf = 1.86 C\/m Kb = 0.512 C\/m Cice = 2.09 J\/g C

Exam 1-solutions - 139 version number signature Yasmeen...

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signature: 139 version number Yasmeen Zubair (ykz57) EXAM 1 Sparks Class (50155) Water Data K f = 1 . 86 C/ m K b = 0 . 512 C/ m C ice = 2 . 09 J/g C C water = 4 . 184 J/g C C steam = 2 . 09 J/g C Δ H fusion = 334 J/g Δ H vapor = 2260 J/g Please refer to the back of the bubble sheet for more info. NOTE: Please keep your Exam copy intact (all pages still stapled). You must turn in your exam copy, plus your bubble sheet, scratch paper, and your free response section.
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Version 139 – Exam 1 – sparks – (50155) 2 This print-out should have 20 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 0014.0pointsThe lattice energy of NaBr is 735 kJ/mol. Theheat of hydration for NaBr is -736 kJ/mol.What is the ΔHsolnfor NaBr dissolving inwater?1.negative ; small 1.1471 kJ/mol2.none of the other answers is correct3.+1 kJ/mol4.-1471 kJ/mol5.-1 kJ/molcorrectExplanation:None0024.0pointsIdentify the FALSE statement aboutKsp.1.Kspis dependent on temperature.2.Kspis called the solubility product for asaturated solution.3.Kspis used to describe salt solutionswhere the minimum amount of salt has beendissolved into the solvent.correct4.Kspis a constant that is specific to eachcompound.5.Kspis a function of the concentrations ofions coming from a given salt.Explanation:Kspis used to describe a solution at satura-tion which is a condition with themaximumconcentration of ions is present (not mini-mum).0034.0pointsA compound is extremely soluble in water.2.negative ; largecorrect3.positive ; small4.positive ; largeExplanation:extremely soluble = spontaneous = nega-tive ΔGextremely soluble = much higher concen-trations when saturated which means a largevalue forKsp0044.0pointsWhat isKspfor Ag3PO4, if its molar solubilityis 2.7×106mol/L?1.5.3×10232.1.7×10143.5.3×10164.2.0×10175.4.8×10226.7.3×10127.1.4×1021correctExplanation:S= 2.7×106mol/LThe solubility equilibrium isAg3PO4(s)3 Ag+(aq) + PO34(aq)[Ag+] = 3S= 8.1×106mol/L[PO34] =S= 2.7×106mol/LKsp= [Ag+]3[PO You would expect Δ G for this dissolution process to be (negative/positive) and that this compound would have a (large/small) K sp value.
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  • Fall '07
  • Holcombe
  • Solubility, Solubility equilibrium

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