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# 3-23, 3-26 - Determine the forces in legs AB AC and AD of...

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Unformatted text preview: Determine the forces in legs AB, AC, and AD of the tripod shown in Fig. 93-23 when force F = 15 1b. The legs can transmit only axial forces. SOLUTION Fm.P\$J3 1-- (0.3992 I - 0.3186 J — 0.8602 2198 25 1 + 40 ' ”4 E = (0.3497 3 + 0.5529 J - 0.9531 E (-0.4190 i + 0.1003 3 - 0.9029 £120 F = -75 E lb FB+FC+FD+F = (0.39stB + 0.34979C - 0.419090} 1 + (-0.31969B + 0.55999 + 0.10039”) + (-0.8602FB - 0.9029FD 0.3982?B 0.4180FD -0.3186FB 0.1003FD -0.8602FB 0.9029FD Solving yields: = -33.42 lb 8 33.4 lb [Cl - -11.62 lb = 11.62 lb (CI ~41.53 1b I 41.5 lb (Cl Two forces are applied in a horizontal plane to a loading ring at the top of a post as shown in Fig. P3—26. The post can transmit only an axial compressive force. Two guy wires AC and BC are used to hold the loading ring in equilibrium. Determine the force transmitted by the post and the forces in the two guy wires. SOLUTION Fig. P3-26 -4 1 + 2 + 10 E ] = (_0.3551 3 + 0.1826 3 - 0.9129 21TH («412 + (2)2 + (-1012 -600 i — 750 3 Thus: R=ZF=TA+TB+FC+FD = (0.371”A - 0.3651TB - 600) i + (0.18stB - T501 3 + (-0.9235':A - 0.91ngB + 1.0000F01 E = 6 0.3714TA - 0.3651TB 600 0.1826TB T50 ”0.9285TA - 0.9129TB + LOOOOFD 0 Solving yields: 5653 N I 5.65 kN {T} 4107 N 3 4.11 kN (T! 8999 N H 9.00 kN {T} ...
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