problem44_45

University Physics with Modern Physics with MasteringPhysics™ (12th Edition)

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44.45: The available energy must be the sum of the final rest masses: (at least) MeV. 136.0 MeV 135.0 MeV) 0.511 ( 2 2 2 2 e a 0 = + = + = c m c m E π For alike target and beam particles: 511 . 0 MeV) 2(0.511
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Unformatted text preview: MeV) (136.0 2 2 2 e 2 e 2 a-=-= c m c m E E e m . MeV 10 81 . 1 ) MeV 10 81 . 1 ( So MeV. 10 81 . 1 MeV 4 2 e 4 4 =- = = c m K...
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This document was uploaded on 02/19/2008.

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