# Math 370 HW 2 - Homework 2 Solution 3-11, 3-12, 3-16, 3-21...

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Homework 2 Solution3-11, 3-12, 3-16, 3-21 (b, c), 3-26 (a, b, c, d), 3-273-11. The intersection of A and B is empty, therefore P(XAB) = 0.a)Yes, since P(XAB) = 0.b)P(XA) = 1 - P(XA) = 10.4 = 0.6c)P(XB) = 1 - P(XB) = 10.6 = 0.4d)P(XAB) = P(XA) + P(XB) - P(XAB) = 0.4 + 0.60 = 13-12.a) P(XA) = 1 - P(XA) = 10.3 = 0.7b) P(XB) = 1 - P(XB) = 10.25 = 0.75c) P(XC) = 1 - P(XC) = 10.6 = 0.4d) A and B are mutually exclusive if P(XAB) = 0.To determine if A and Bare mutually exclusive, solve thefollowing for P(XAB):P(XAB) = P(XA) + P(XB) - P(XAB)0.55 = 0.3 + 0.25 - P(XAB)0.55 = 0.55 - P(XAB) and P(XAB) = 0.Therefore, A and B are mutually exclusive.e) B and C are mutually exclusive if P(XBC) = 0.To determine if B and Care mutually exclusive, solve thefollowing for P(XBC):P(XBC) = P(XB) + P(XC) - P(XBC)0.70 = 0.25 + 0.60 - P(XBC)0.70 = 0.85 - P(XBC) and P(XBC) = 0.15.

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