Math 370 HW 8 - Homework 8 5-40, 5-43, 5-44, 5-51, 5-57,...

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1Homework 85-40, 5-43, 5-44, 5-51, 5-57, 5-585-40.d= 868.375sd= 1290, n = 8 where di= brand 1 - brand 299% confidence interval:dtsndtsnnddnd / ,/ ,2121868375349912908868375349912908.... d727.46d2464.21Because zero is contained within this interval, there is no significant difference between the two brands of tire.5-43.a) 1) The parameter of interest is the mean difference in natural vibration frequencies,dwhere di= Finite ElementEquivalent Plate.2) H0:d03) H1:d04) The test statistic istdsnd0/5) Reject the null hypothesis if t0>1,2/ntwhere6,025.0t= -2.447 or t0>1,2/ntwhere6,025.0t= 2.4476)d5.49,sd5.924, n = 7t0549592472 45 ../.7) P-value = 2P(T < -2.45), thus 0.01 < P-value < 0.025Because the P-value < 0.05, we reject the null hypothesis and conclude that the two methods produce significantly

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