problem44_15

University Physics with Modern Physics with MasteringPhysics™ (12th Edition)

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44.15: a) With 2 2 a 2 2 , mc E E mc E m m = Eq. (44.11). So GeV. 3190 GeV) 938 . 0 ( 2 GeV)] 7 . 38 ( 2 [ 2 = = m E b) For colliding beams the available energy a E is that of both beams. So two
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Unformatted text preview: proton beams colliding would each need energy of 38.7 GeV to give a total of 77.4 GeV....
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This document was uploaded on 02/19/2008.

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