problem44_51

University Physics with Modern Physics with MasteringPhysics™ (12th Edition)

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44.51: a) 2 2 2 p 2 ) ( ) ( ) ( ) ( c m c m c m c m E K K - - - = = + MeV. 32.0 MeV) 2(493.7 MeV 1019.4 = - = Each kaon gets half the energy so the kinetic energy of the + K is 16.0 MeV. b) Since the 0 π mass is greater than the energy left over in part (a), it could not have
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Unformatted text preview: been produced in addition to the kaons. c) Conservation of strangeness will not allow .-+-+ + → + → μ φ K or K...
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This document was uploaded on 02/19/2008.

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