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Fall05-ECT-Exam2-solution

Fall05-ECT-Exam2-solution - Name WWWWMM “MM" WWW...

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Unformatted text preview: Name WWWWMM “MM" WWW ID #mw WW W mm m mm “x {oh <1)? ‘1 BESWALMWMMWHWWM WWW-WWWWWWWWWMMMMW Wm M M The OP, AMPS m a“ the circuits shown are assumed to be idea! and the Supply voltages Vt: :2 $15 V a) For the circuit below, find the current i as shown. ”“2 @ hm“ WW5 V 8a ‘1": ‘3 U 9W“) 9““00 :7; Q‘me‘ (OK th ”0 3 3L CF :- 0 Va :- “n w ’L kin :: 0 V6 3 ‘EML \llO.Un , V0: LAVVV , I @9233; $535 ,, V, __ , fig I: 602 MA C) For the Circuit below, find V00) in terms of 1210‘), v20), R1 ,R2 and C a “Fxrcsm (DOTWMR W'WW %€)§ 0‘91" (:3 Ugjgth % KQL mcfiom} WNA/wa £26“: 95%;“ 4; (3:3 WNQJW R 0 w Ci‘ifim w m @MWTQ; ‘ m ‘ Matti WC; math-r: “23(0) “”8 écgwm‘gh “EC; WU Cnafib a o : VpsUh ‘5 \Q N9 éW‘iD Name: .MWVWWMWWWWM ED # b) For the circuit bwélOW mmmWWmmm“MWWWMIWWW—WMMMWMHWWMMMWWMMMM @ find 1203 in terms ofihe input voltages V and V2 1 @ \J‘ony w UVH'SZO « U Q U \ m % \TCL “tacit Y“ ‘1 QM) ”“r (\M v {:3 35? V a V‘ 45 s M g. m 63? Rm? % 2= Wm/NMM; a v92 :: <3 39): ”my“ ,0 a; kckm wig, Ga 0 Riggm‘v?‘ \gflUm Wéfim‘“ E Q WW W” WWW-mm” ~ kmmmmamm :WQ 0%: 33%? mm Uggz”; ”4&3 Va m fiwgi @ghfim‘? #5 WMMVAWWW ‘ . (3 U93; :2: Wm“ $6” W3 W Q‘WCu “(39151” W33 *3 97‘3”“? ~12“ Umbgg” <3 Uegm3wfi§ 5) may? 3mm , Wes): 'V'i‘éVwfiCWa i .WR5§“[email protected]~% 9 Find V03 for V121 Vandez2V mm Name: iii) tit floblem (2) W__m_m._mmmmw m For the circuit shown, the switch was open for long time and it is; closed at Z 41' O a) At t = 0+ , find the capacitor voltage VC(0+) and the capacitor current ic (0+) ”t M 4‘31“} if; T icto )3: “67E“ W “" ) )V m 2. , N t: 0 ‘C(0) ‘V "E; m“ WVW 5,” t. if: ”gm“ on “i" ‘3 can b) At t = 00 , find the capacitor voltage vc(<>0) and the capacitor current ic (00) mm m um) i Moo) e \t moot ::~ 0 c) Find the circuit time constant ’1': at t 2 0+ “to: RQUKAQ 9%: étS/l’étc x "in“ d) Find capacitor voltage 1260‘) for i 2 03mg % a ‘ q “”‘ 9:130 "Mir Mcfl’k):; £3 3%. L by» Q; l E; “it ZR} e) Find capacitor current ic(l‘) for t 2 0+ . m iii: “t" Cutie C3 WM; “if“ m (:31 a *5 gig-<3 s») t) Sketch VC(Z) and ic(t) for 1‘2 0+ ”3., Name: ”-3 it“ Probiem (3) m m W _ For the circuit shown, the switch was open for long time and it is ciosed at Z r 0. ”tug“ WM b) Find the Thevenin equivalent circuit seen by the inductor when the switch is closed. Ate-<5“ Wu F * my; lettffiimw‘tgv LQ” Vesta :2 (@1363: a: :2»: Q W wig}? ":2:: M” 6 \jeléi Find the inductor current iL (0+) when the switch is ciosed {is («Cf ) :2 IL A d) Find the inductorcurrent iL(°0) when the switch is closed \fiifi L.%3m W2; A e) Find the circuit time constant ’1? at l 2 0+ 663'»?le "4*: SM :2 :5 WWW»: m; s 2m f) Find inductor current iL(l) for I 2 0+ {3 E; _ kegs mat, whim «as: "1 e ‘ {LLt):‘; swag ; A -4- ”L223“ Name: lD# Problem (4) WWWWWW H. For the circuit shown, the switch was in position (a a)for long time and it lS moved to position (b ) at l‘ m 0‘ a r: 0 4 £2 W411,” WW “WW “mm “W” aw1,.\MXANWWWTWWWW. ngZL l 1 air (jg) it; E 6 .Q i ’é :1 (:3th a) At t 2 0* , find the capacitor voltage vL.(0fi) and the inductor current iL (0‘) (6) WWI)” gawk? {$46) :2 096?; A b) At t: 00 , find the capacitor voltage vc(°0) and the inductor currentiL(°<>) Li; wcgm) 3 MEAN. Ce) we NCCWDEE 6K5” c) The differential equation describing the circuit in terms of VC for l 2 0+ , found to be : dzv m 12m 1% dr 011‘ C * mix 4Q Predict the differential equation describing the circuit in terms of iL it W] ac “ij %$ati%”awtimmwi New iiwitsfiahx we) d) Write the characteristic equation for the obtain differential equation. e) Find the roots of the obtained characteristic equation _ / WWWWWP game Iae 32m3§f([email protected] ’ , g S 2, meg rad 1 & Name: lD # 3’) Write the solution form for 1/60) in terms of constants and define its: type ( overdamped, critically damped or underdamped) .5 n {i m (:E“ ML. (E) 2; Q ME» Rs C; we 9w. “E (g? «43 9) Find the solution for vc(t) 1min»; mil, CmncEiEionéa “E: :2 :2? WW ‘3 (@4417, :2" 'L \C) mfljiéfl EEE‘E E: \0«&& 1% lam ffié’N’Q‘é ice” M332: Emil Baojml {El 9% (EEQELERQW figm N6: (C3) 2:: CE; «Em QE ”gm Rafi mm '3 (5; Wm Q a WVWM @E EEQ NAB/WV s wwmmmmwmwwVMWWE EEE WHERE wax “33?qu Km, “E m “Em m mm)‘ 333, 9mm (E3 EX (:2?) 663% El: 3E5 6'3:— «E4 ENE. ”lb ‘EEE ENC“ CE) :2: ”w Ma. +0 2:? @5153 ”E Name: M M V “ ,n H) 9%. ’2 3;" r: CM :2: \Q ‘i‘mfi [1 g3}, .. \W 523m a; 2sz 3‘39 v; : 50cos(1000z + 45 ) V 7 W‘g :2 WE?) mgr; Wm: “22f”: Moor; ’ a) Transform the circuit shown from the time domain to the phasor (frequency ) domain r500 weer: «We» ° " » 2.: 100C) J2, ~ [new :1 v I a b) Find the phasor current I a 550 Q 1: ’50 Lfi WWFEEWLEWW 539%: 2 m eoo Mk» fieoom moo 2300 m» [$66 Naomi) mfi _, ,_ 3 1:: mimmfieflgm ix “omoeolmi bi» A C) Find the phasorvoitage V0 r“. “:21? " “WM “at“ "‘ \{Q 3: Cl) (“Xe ) :: Lg‘gwf £3,311 L mfilmfil ::2 L” wwwwwwwwwwwww j {0 Lomwwi :éfi‘fe mfg; fl : 593 a? ,, 5, £23 " 6E9 1WM”“” V533 “313““? i“ LCQW V d) Find the sinusoidal steady state response 120 (Z) mmb‘w ‘00 (3&5) b00681 \l 32 ”afidoéii (Sofie moon U: e) Sketch the waveform of vs( I) and 1100‘) on the same graph and define the leading waveform. Raw ...
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