# Homework 1 - 1 PHYS-1200 PHYSICS II HOMEWORK#1 SOLUTIONS...

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Unformatted text preview: 1 PHYS-1200 PHYSICS II HOMEWORK #1 SOLUTIONS 21.10. a) The forces on Q due to q 1 and q 2 must be directed opposite to each other if they are to add to zero. Q is between q 1 and q 2 , so q 1 and q 2 will produce forces on Q that are in opposite directions if they are of the same sign. Therefore, they must be of the same sign, whether positive or negative. The distance between q 1 and Q is a + a /2 = 1.5 a . Then the magnitude of the force produced by q 1 is: 2 1 1 ) 5 . 1 ( 4 1 a Q q F πε = The distance between q 2 and Q is a – a /2 = 0.5 a , so the magnitude of the force produced by q 2 is: 2 2 2 ) 5 . ( 4 1 a Q q F πε = . Since these forces are in opposite directions, their magnitudes must be equal to produce a force of zero. Then: 2 2 2 1 ) 5 . ( 4 1 ) 5 . 1 ( 4 1 a Q q a Q q πε πε = , or 2 2 2 1 ) 5 . ( ) 5 . 1 ( q q = , so 2 2 2 2 2 1 9 3 5 . 5 . 1 q q q q = = = 9 2 1 = q q b) Since Q is not between q 1 and q 2 they must be of opposite signs if the forces they...
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## This note was uploaded on 04/17/2008 for the course PHYSICS 1200 taught by Professor Peterpersans during the Spring '08 term at Rensselaer Polytechnic Institute.

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Homework 1 - 1 PHYS-1200 PHYSICS II HOMEWORK#1 SOLUTIONS...

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