Estructuras_secuenciales_26

Estructuras_secuenciales_26 - cin>>n for(i=1;i<=n;i...

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#include <iostream> #include <math.h> #include <conio.h> using namespace std; int main() { //HALLAR (5*i)/(pow(i,2)) para "n" terminos... Problema 26! int n,i; double t,suma; cout<<"Ingrese numero de terminos: ";
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Unformatted text preview: cin>>n; for(i=1;i<=n;i++) { t=(5*i)/(pow(i,2)); suma=suma+t; } cout<<endl<<"El resultado es: "<<suma<<endl; system ("PAUSE"); return 0; }...
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