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problem40_14 - 2 2 2 out U m h U E m h =-= Thus the ratio...

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40.14: According to Eq.40.17, the wavelength of the electron inside of the square well is given by . ) 3 ( 2 λ 2 0 in U m h mE k = = By an analysis similar to that used to derive Eq.40.17, we can show that outside the box
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Unformatted text preview: . ) 2 ( 2 ) ( 2 λ out U m h U E m h =-= Thus, the ratio of the wavelengths is . 2 3 ) 2 ( 2 ) 3 ( 2 λ λ in out = = U m U m...
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