Solution_HW2

Solution_HW2 - Solutions for homework set#2 Problem#1 Two...

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Solutions for homework set #2: Problem #1: Two parallel flat plates, area 929.0304 cm 2 , are spaced 3.048 cm apart. The lower plate is moving with a velocity of 3.048 cm/s while the top plate is at rest. If the force required to move the plate is 0.0002765 N, find the viscosity of the oil between the plates. Answer: The shear stress is 2 -4 0.0002765 0.003 N/m 929.0304(10 ) τ == and the shear rate is -1 1 s γ =− ± Newton’s law of viscosity gives 2 0.003 N.s/m µ = ± Problem #2 : The rheological properties of a particular suspension used in hydraulic fracturing can be approximated reasonably well by either a “power law” or a “Bingham plastic” model over the shear rate range of 10 to 50 s -1 . If the consistency index K is 10 Ns n /m 2 and the flow behavior index n is 0.2 in the power law model, what will be the approximate values of the yield stress and of the plastic viscosity in the Bingham plastic model? Answers Using the power law model 0.2 10 n K γγ ±± When 12 10 ; 15.85 N/m 50 ; 21.87 N/m s s γτ ± ± Using Bingham Plastic model yp τη =+ ± When

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This note was uploaded on 04/17/2008 for the course PGE 322K taught by Professor Dicarlo during the Fall '08 term at University of Texas.

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Solution_HW2 - Solutions for homework set#2 Problem#1 Two...

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