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Unformatted text preview: ( 29 ( 29 ( 29 568 . , 512 . 028 . 54 . 96 . 1 54 . ˆ 1225 54 . 1 54 . ˆ 1 ˆ 025 . ⇒ ± ⇒ ± ⇒ ± n p p z p STA 301 – Applied Statistics Spring 2008, Section B Homework #10  Key Due Wednesday, April 16 Question 1 : Prior to a national election, a Democratic campaign staffer conducted an opinion poll to determine the percentage of votes his candidate could expect to receive. He collected a random sample of 1225 likely voters, 54% of whom planned to vote for the Democratic candidate. (a) Construct a 95% confidence interval for the true percentage of people who would vote for the Democratic candidate in the election. (b) At the 95% confidence level, could the staffer conclude that the Democratic candidate would win the election? Why or why not? The candidate needs over 50% of the vote to win the election. Since the entire confidence interval is above 50%, the staffer can conclude, with 95% confidence, that the Democratic candidate will win. (c) Extra credit! (I’m not kidding.) Assume the only other candidate on the ballot was a Republican, and there were no writein votes cast. Construct a 95% confidence interval for the Democrat’s margin of victory (or loss, if negative). Margin of victory is the difference in the proportion of votes received by the Democrat and the proportion of votes received by the Republican....
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This homework help was uploaded on 04/17/2008 for the course STA 301 taught by Professor Noe during the Spring '08 term at Miami University.
 Spring '08
 Noe
 Statistics

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