problem35_12

problem35_12 - mm 8.00 m 10(0.200 m 10(400 m 00 4 3 9 1 = =...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
35.12: The width of a bright fringe can be defined to be the distance between its two adjacent destructive minima. Assuming the small angle formula for destructive interference , λ ) ( 2 1 d m R y m + = the distance between any two successive minima is
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: mm. 8.00 m) 10 (0.200 m) 10 (400 m) 00 . 4 ( 3 9 1 = = =---+ d R y y n n Thus, the answer to both part (a) and part (b) is that the width is 8.00 mm....
View Full Document

This note was uploaded on 01/31/2009 for the course PHYS 221 taught by Professor Hu during the Spring '08 term at Texas A&M.

Ask a homework question - tutors are online