problem35_13

problem35_13 - fringe is located by sin 2 2 where , 2 d =...

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35.13: Use the information given about the bright fringe to find the distance d between the two slits: . m 10 3.72 m 10 4.84 m) 10 (600 m) (3.00 λ so ), 6 . 35 . Eq ( λ 4 3 9 1 1 1 1 - - - × = × × = = = y R d d R y ( R is much greater than d , so Eq.35.6 is valid.) The dark fringes are located by . . . , 2 , 1 , 0 , λ ) ( sin 2 1 ± ± = + = m m d θ The first order dark
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Unformatted text preview: fringe is located by sin 2 2 where , 2 d = is the wavelength we are seeking. d R R R y 2 sin tan 2 = = We want 2 such that . 1 y y = This gives 1200 2 and 2 1 2 2 1 = = = d R d R nm....
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This note was uploaded on 01/31/2009 for the course PHYS 221 taught by Professor Hu during the Spring '08 term at Texas A&M.

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