problem35_15

problem35_15 - m 10 3(5.50 arcsin 2 3 arcsin 6 7 2 d m...

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35.15: We need to find the positions of the first and second dark lines: . m 0.0541 ) tan(8.79 m) 0.350 ( tan 79 . 8 m 10 2(1.80 m 10 5.50 arcsin 2 λ arcsin 1 1 6 7 1 = ° = = ° = × × = = - - θ R y d Also ° = × × = = - - 3 . 27 m) 10 2(1.80
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Unformatted text preview: m) 10 3(5.50 arcsin 2 λ 3 arcsin 6 7 2 d m. 0.1805 tan(27.30) m) 35 . ( tan 2 2 = = ⇒ θ R y The fringe separation is then . m 0.1264 m 0.0541 m 1805 . 1 2 =-=-= ∆ y y y...
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This note was uploaded on 01/31/2009 for the course PHYS 221 taught by Professor Hu during the Spring '08 term at Texas A&M.

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