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problem35_16 - 35.16(a)Dark fringe implies destructive...

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35.16: (a) Dark fringe implies destructive interference. λ 2 1 sin = θ d m 10 64 . 1 0 . 11 sin 2 m 10 624 sin 2 λ 6 9 - - × = ° × = = θ d (b) Bright fringes: λ sin max max m θ d = The largest that θ can be is m d m Since 6 . 2 λ / so , 90 m 10 624 m 10 1.64 max 9 6 = = = ° - - × × is an integer, its maximum value is 2. There are 5 bright fringes, the central spot and 2 on each side of it.
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