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problem35_31

problem35_31 - 2 so 1 1 = = tn m The condition for...

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35.31: Destructive interference for 800 λ 1 = nm incident light. Let n be the refractive index of the oil. There is a 2 / λ phase shift for the reflection at the air-oil interface but no phase shift for the reflection at the oil-water interface. Therefore, there is a net 2 / λ phase difference due to the reflections, and the condition for destructive interference is ). / λ ( 2 n m t = Smallest nonzero thickness means .
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Unformatted text preview: λ 2 so , 1 1 = = tn m The condition for constructive interference with incident wavelength λ is on so and nm, 320 λ 2, for nm 533 λ , 1 for nm 1600 λ , for nm. 800 λ where ), /( λ λ so , λ 2 But . λ ) ( 2 and ) / λ )( ( 2 1 2 1 1 1 2 1 2 1 = = = = = = = + = = + = + = m m m m tn m tn n m t The visible wavelength for which there is constructive interference is 533 nm....
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