problem35_32

problem35_32 - difference is a half-integer multiple of the...

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35.32: a) The number of wavelengths is given by the total extra distance traveled, divided by the wavelength, so the number is . 5 . 36 m 10 6.48 (1.35) m) 10 76 . 8 ( 2 λ 2 λ 7 6 0 = × × = = - - tn x b) The phase difference for the two parts of the light is zero because the path
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Unformatted text preview: difference is a half-integer multiple of the wavelength and the top surface reflection has a half-cycle phase shift, while the bottom surface does not....
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