problem35_32 - difference is a half-integer multiple of the...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
35.32: a) The number of wavelengths is given by the total extra distance traveled, divided by the wavelength, so the number is . 5 . 36 m 10 6.48 (1.35) m) 10 76 . 8 ( 2 λ 2 λ 7 6 0 = × × = = - - tn x b) The phase difference for the two parts of the light is zero because the path
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: difference is a half-integer multiple of the wavelength and the top surface reflection has a half-cycle phase shift, while the bottom surface does not....
View Full Document

This note was uploaded on 01/31/2009 for the course PHYS 221 taught by Professor Hu during the Spring '08 term at Texas A&M.

Ask a homework question - tutors are online