problem35_35

problem35_35 - 1 = m , the wavelength is 514 nm, which is...

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35.35: a) To have a strong reflection, constructive interference is desired. One part of the light undergoes a half-cycle phase shift, so: . 2 1 nm 771 2 1 (1.33) nm) 290 ( 2 2 1 2 λ λ 2 1 2 + = + = + = + = m m m dn n m d For an integer value of zero, the wavelength is not visible (infrared) but for
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Unformatted text preview: 1 = m , the wavelength is 514 nm, which is green. b) When the wall thickness is 340 nm, the first visible constructive interference occurs again for + = = 2 1 nm 904 yields and 1 m m = 603 nm, which is orange....
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This note was uploaded on 01/31/2009 for the course PHYS 221 taught by Professor Hu during the Spring '08 term at Texas A&M.

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